6x^2-27x+7=0

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Solution for 6x^2-27x+7=0 equation:



6x^2-27x+7=0
a = 6; b = -27; c = +7;
Δ = b2-4ac
Δ = -272-4·6·7
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{561}}{2*6}=\frac{27-\sqrt{561}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{561}}{2*6}=\frac{27+\sqrt{561}}{12} $

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